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Intruder alarm system
8EP 394 XR1 G3 panel with built-in keypad
Operating Instructions
These operating instructions cover the following intruder system:
Attack Tamper
8EP 394 XR1G3 panel with built in keypad
LED steady On indication LED flashing indication LED Off Internal sound
Sound description
Unset system indications
An unset system will have both Day and Power indicators lit. This is a normal Day Power indication when the system is disarmed.
NOTE: In general a flat beep is an indication of an incorrect key press. External devices Strobe Bell
Note: If the Power indicator goes off at any time then there is a mains supply failure at the security panel, consult your servicing organisation.
Set System indication
An active Set system will have only the Power Power indicator lit. This is an armed system indication.
4188-693 issue 1_8/01
Accenta /! mini
For Clarity, the information given on setting the system, assume that all Programs use a timed or final door setting routine.
Operating instructions
Contents
Unset system indications - - - - - - - - Set System indication - - - - - - - - - Access codes - - - - - - - - - - - - - How to operate Personal Attack - - - How to unset system in alarm - - - - - Programs 1, 2 and 3 - - - - - - - - - - How to set the system (on program 1) - Push to Set Switch - - - - - - - - - - - Keyswitch Set - - - - - - - - - - - - - Faults during setting - - - - - - - - - - How to unset the system (turn off) - - How to set program1,2 or 3 - - - - - - How to Quick set - - - - - - - - - - - How to Omit zone(s) on setting system Fire Alarm - - - - - - - - - - - - - - How to set Chime Zones - - - - - - - Operators Program mode - - - - - - - To exit operation at any time - - - - - - How to enter Operators program mode How to view the events log - - - - - - How to create/omit User 2 code - - - - How to change current user code - - - How to carry out Alarm and Walk testsServicing organisation details - - - - - - Quick Reference - - - - - - - - - - - - 8
Citadel XR1 G3 Intruder system
How to unset system in alarm
Enter your code. Entering the code will turn the alarm off and the cause of the alarm will be displayed. After investigation press Reset to clear the indication.
n n n n
FIRST ZONE IN ALARM OTHER ZONES IN ALARM
Investigate the Alarm
ALL ZONE
Strobe Off
Access codes
Note: If the alarm indication does not clear, then the system may need to be reset by the installation engineer, contact your installer for further information.
Programs 1, 2 and 3 Access codes
There are two User codes used in the system, both are 4 digit and can be set to any number from 0000 to 9999, signified by:
The user 1 and 2 codes have the same operation for testing, Setting and Unsetting, but user 1 code which is usually considered to be the Managers code has the authority to add, change or delete the user 2 code.
The panel uses 3 Part Set routines known as Programs. In each Program the exit mode can be changed and the zone may be set up to have a different function. The examples below show how 3 typical Programs could be used in a house. Program 1 To arm all of the zones and become Set as the user leaves the property and closes the final door. Program 2 To protect the perimeter of the property in the evening and become Set after say 20 seconds. Program 3 To protect the downstairs areas of the house at night and become Set silently. The above are purely examples. The installer has the ability at the programming stage to configure all the circuits to the customers exact requirements.
User 1 code - 0123 factory set User 2 code - not programmed.
How to operate Personal Attack
Personal Attack buttons on the keypad are used to activate the alarm, irrespective of whether the system is armed or not. Press Simultaneously: 9 4
Citadel XR1 G3 intruder system
How to set the system (on program 1)
The green Day indicator should be showing. Enter your code number and check that the system is clear (none of the Day zone indicators are showing). The n n n n sounder will now 10seconds produce an exit Exit beep insistent beeps beep tone and you should leave by Day the approved route. The system will Set as the beep tone stops.
How to unset the system (turn off)
On entering the premises an entry beep tone come on. Enter your code, the green Day indicator is lit. The system is unset and disarmed.
Entry beep Day
Acknowledge Day
Push to Set Switch
In some systems a Push to Set switch may be fitted outside the premises near to the main exit door. This should be used to complete the setting How to set program 1,2 or 3 procedure once the building has been vacated. As the switch is operated, the exit beep tone will The green Day indicator should be showing. stop and a chime tone will be produced to Enter your code Day acknowledge setting. number and the exit beep tone n n n n will start. Press Exit beep the Prog key and Keyswitch Set the exit tone will ZONE 1-3 Prog Exit beep stop. Press 1, 2 Your system may have been fitted with a remote or 3 for the keyswitch. This can be used as an alternative to 2 Or required arming the system with a code and will set program, the Program 1. 10 seconds Exit beep insistent beeps sounder will Where a keyswitch is used it may be necessary beep to Day on occasions to allow it to catch up with the acknowledge the system. For example if the alarm was set with a code, to Unset with the keyswitch, it would have program number. The exit beep tone will start to be momentarily turned to Set then returned to and you should leave by the approved route. The system will Set as the beep tone stops. Unset. It is important that you follow the correct procedure when setting the system. After leaving the protected area it is absolutely essential that you wait until the exit tone stops, before assuming the system has set.
Faults during setting
If the system is not clear when you try to Set it, the sounder will produce an open zone tone and the fault will be displayed. Either re-enter your code to turn off and investigate or omit the faulty zone(s) from the system.
How to Quick set
During the exit period (on entering User code) the system may be Set quickly by pressing Set. Day Set the system or This removes the exit time period. Set a Program
5 seconds insistent beeps Day
How to set Chime Zones
Example: To set zone 3 and 4 to chime, Press:
If you omit zones and require Quick Set, you will need to press Set twice.
Timeout after 5 seconds if no selection is made
Day Chime
Deselect all zones (Factory default - no chime) Zone 1 Zone 2 Zone 3 Zone 4 Zone 5 Zone 6 Zone 7 Zone 8 Appropriate Zone indicator is lit to show chime zone(s)
Zone n Chime selected Zone n Chime deselected
How to Omit zone(s) on setting system
Press number button to select / deselect Zone Chime
During the exit period after entering User code and selecting a program press Day OMIT, the exit Set the system or tone will stop and Set a Program and while the zones that are system is setting: about to be armed will be displayed. Omit ZONE(S) TO BE ARMED Key in the zone Exit beep number(s) to be omitted which will Press the zone(s) n flash to confirm to be omitted selection. Zone ZONE(S) TO BE OMITTED indicators which show steady are Set still about to be 10 seconds Exit beep armed. When the insistent beeps selection is Day complete press Set and the exit tone will start. If a zone refuses to be omitted, it may be because the engineer has programmed the panel to prevent you from turning off the zone. If in doubt ask your installer for advice.
Leave chime mode
Fire Alarm
The fire zone will operate on detection of a fire, whether the system is Set or Unset, when configured as a 24 hour zone, and cause a distinctive internal sounder tone. The external sounders will pulse on and off at 2 second intervals and zone indicator will flash to attract attention.
Chime is a low security monitoring system for use when the system is Unset. When a zone that is set to chime is operated, the internal sounder will produce a low volume two stage warning tone and the Zone indicator will show. The indicator may be cancelled by pressing Reset. Chime is particularly useful in a shop to warn of a customer presence or in a house to warn that a door or particular area has been accessed. Any zone may set to be on or off chime by pressing the CHIME key and then keying in the required zone number(s). Key 0 to cancel all zones from chime. After a few seconds the system will automatically return to the Day mode.
Operators Program mode
The information below shows the programmable options available and how to change them. Once the operator program mode has been accessed, each section may be changed in any order. As each operation is completed the system will automatically return to top level of program mode.
How to view the events log
The panel can hold up to 8 previous events which can be scrolled automatically or manually. The automatic scroll starts with the newest event ( number 8) to the oldest one ( number 1).
Example: To view up to 8 previous events and thereafter to stop the event scroll, Press: Prog Chime
Note: When programming the system should be in the Day mode, with the Day and Power indicators lit.
Enter Operators program mode
View the event log
Tamper
To exit operation at any time
On pressing the Reset key you will quit the current level of operation.
Automatic event scroll Starting from event 1 to 8 To manually scroll View event (oldest event)
Zone, PA and Tamper indicators will be lit to show zone in alarm. Flashing indicates the first zone in alarm. Day indicates status of panel at the time of alarm
Quit the current function Leave Engineering menu Down one menu level
View event 2 View event 3 View event 4 View event 5 View event 6 View event 7
How to enter Operators program mode
To enter the Operators program mode the system should be in Day Prog mode with the Day and ZONE 1 - 8 Power indicator lit. Momentarily On
8 View event 8 (Newest event) Chime Resume automatic scroll
Acknowledge
Stop event scroll / view Leave program mode
Day Acknowledge Tamper
How to create/omit User 2 code
User 1 code which is usually considered to be the Managers code has the authority to add, change or delete the user 2 code.
Example: To create user 2 code 4567, Press:
How to change current user code
You can change the current user 1 or user 2 code for security reason.
Example: To change user 1 code from 0123 to 7777, Press:
Enter Operators program mode Change / omit User code (By user 1 only)
Attack
Change the code of Current user (either User 1 or User 2)
ZONE 1-4
n New code
Current user new code
NOTE - The sounder will produce a flat beep if code is rejected.
Rising beeps
To omit the user 2 code
NOTE - Factory default code for User 2 is not programmed
Leave program mode
How to carry out Alarm and Walk tests
The alarm test function allows you to test the Strobe, Bell, Low and High volume sounders of the system. The walk test function allows each detector to be checked in order to verify that they are functioning correctly.
Example: To start bell test and thereafter to stop bell test. Prog 0 Reset Reset Enter Operators program mode
0 Alarm test
Press zero to turn off options 2,3,4 and 5 before selecting a new one
Strobe test
Strobe On Bell on
3 Bell test 6
Low volume sounder High volume sounder Walk test
internal low volume sound internal high volume sound Strobe
Strobe On
x1 for zone 1 x2 for zone 2 | x4 for zone 4 flat x1 for zone 5 flat x2 for zone 6 | flat x4 for zone 8 Rapid for PA Rapid for Tamper
Appropriate zone lights are lit(latched) Zones
Exit current level
Servicing organisation details
Servicing organisation name: ______________________________________ Telephone number: ______________________________________ Date of installation: ______________________________________ Account Number: ______________________________________ Installation Date: ______________________________________
Bell Time:_____________________________ Bell delay______________________________ Area protected Zone 1 Zone 2 Zone 3 Zone 4 Zone 5 Zone 6 Zone 7 Zone 8 T = Timed (Entry/Exit - Zone) TI = Time Inhibited (Access zone to keypad) I = Immediate (All zones armed to give full alarm) Program 1 Program 2 Program 3
Quick Reference
To Set a Program
Day Entry beep Day Day
To Set the system (Program 1)
n n n n n n n n
To Un-set the system To Quick Set the system Bell
To Reset Alarm state
To Omit zones on Setting system
Exit beep
Exit beep Acknowledge
FIRST ZONE IN ALARM
OTHER ZONES IN ALARM
Set the system or Set a Program
ZONE(S) TO BE ARMED
ZONE 1-3
Set the system or Set a Program and while the system is setting:
10seconds insistent beeps
Or Day Day 10 seconds insistent beeps
Exit beep Day
5 seconds insistent beeps
Press the zone(s) to be omitted
ZONE(S) TO BE OMITTED
The panel conform to the requirements of the European EMC and Low Voltage directives, and carries the CE mark.
Exit beep 10 seconds insistent beeps Day
Operators program mode menu map
To set Chime zone
To exit Operators program mode
Operators Progam Mode Prog
n n n 7
Alarm test Change / omit User code 2 (By user 1 only) Change the code of Current user (either User 1 or User 2) View the event log
Zone to chime
Automatic event scroll Starting from event 1 to 8 For manual scroll
3 Bell test
Leave program mode View event 1 (oldest event) Leave program mode
View event 8 (Newest event)
Low volume sounder
Normal indications of an Unset system
Day Power
High volume sounder
Walk test Press zero to turn off options 2,3,4 and 5 before selecting a new one
Resume automatic scroll
Alarm indications Bell On
Stop event scroll / view
Strobe Tamper / Service warning
Quit the current function Leave program menu Down one menu level

5.2 Solutions about Singular Points Consider a second order linear differential equation of the form: a2 x y The standard form of 1 is y Px y Qx y 0 where P x a1 x , and Q x a2 x a0 x. a2 x 2 a1 x y a0 x y 0. 1
The general solution of the equation in 1 is y C 1 y 1 C 2 y 2. As described in the last Chapter, there exist two linearly independent solutions of 1 in the form of a power series centered at x 0 where x 0 is an ordinary point of the equation. In this section, we will look into to the possibility of finding a power series solution or a power series like solution centered at x 0 when x 0 is a singular point of the equation. 1. Regular and Irregular Singular Points: Definition: Let x 0 be a singular point of the equation 1. x 0 is said to be a regular singular point if both functions a x a x x x0 P x and x x0 2Q x x x0 x xa2 x a2 x are analytic at x 0. x 0 is said to be an irregular singular point if it is not regular. Example Find all singular points of the equation and for each singular point determine if it is regular singular or irregular singular. a. x x 1 y 2 x 2 y xy 0 y 2y 0 b. x 2 y xx and a 0 x 2 are polynomials. The a. a 2 x 0 when x 0, x 1, and a 1 x differential equation has 2 singular points: x 0, and x 1. Determine now if these singular points are regular or irregular. i. Consider x 0 : 1 , 2x. x2Q x x2 xP x x x 1 x 1 xx 1 xx 1 Since both 1 and 2x are analytic at x 0, x 0 is a regular singular point. x 1 x 1 ii. Consider x 1 : 2x 1 1, x 1 2Q x x 1 2. x 1 Px x 1 x x xx 1 xx 1 2x 1 are analytic at x 1, x 1 is a regular singular point. Since both 1 and x x b. a 2 x x when x 0, and a 1 x 2 x 2 and a 0 x x are polynomials. The differential equation has 1 singular point: x 0. Determine now if this singular point is regular or irregular. Check x2. xP x x 2 2x x x Since xP x is not analytic at x 0, x 0 is an irregular singular point. 2. Frobenius Theorem: Let x x 0 be a regular singular point of the equation 1. Then there exists at least one solution of the form 1
where r is a constant to be determined so that c 0 series is convergent at least on the interval 0 x Note that when x 0 is a regular singular point, cm x x0
0. There also exists a constant R x 0 R. cm x
0 such that the power
there may not be two linearly independent solutions in the form of
is not a power series if r is not a nonnegative integer.
Cauchy - Euler equations: a2x2y bxy cy 0 where a, b and c are given constants 3xy 4y 0 has two linearly independent solutions: is a special case. For example, the equation: x 2 y 2 and y 2 x 2 ln x. y1 x Since ln x is not defined at x 0, y 2 does not have a power series in the powers of x. Three Possible Cases for the Solutions y 1 and y 2 : i. r 2 r 1. Let y 1 c x m r 1 c be a solution of the equation. Use the method of reduction of order to m 0 m derive the second solution y 2 , Let y 2 u x y 1. Then u y2 u x y1 y 1 e yy1 C1y1
P x dx
1 y2 1
Note that the solution y 2 can also be represented by a power series since y 1 , y 2 , 12 , e 1 y1 power series form. ii. r 2 r 1 and r 2 r 1 an integer. Then y1 y2 y x r1
are in
c m1 x m
c m1 x m c m2 x m
, where c 01 , where c 02
0, 0, and
c m2 x m C2y2.
iii. r 2 r 1 and r 2 r 1 N a positive integer. c x m r 1 and y 2 c x m r 2. There are 2 situations: Let y 1 m 0 m1 m 0 m2 a y 1 and y 2 are linearly independent, then y C 1 y 1 C 2 y 2. b y 1 and y 2 are linearly dependent, or only one solution, say y 1 is derived, then compute y 2 by the formula in 3 and y C 1 y 1 C 2 y 2. Frobenius Method: Let x 0 be a regular singular point of a given differential equation a2 x y a 1 x y a 0 x y 0. 2
Find a solution of the equation of the form: y
Steps: a. Compute y
b. Substitute y, y and y into the differential equation and simplify. c. Solve r so that c and for each solved r find the recurrence relation for c m and express c m in terms of m if possible. d. If there exists only one solution y 1 which is in the form of a power series, then compute y 2 : y2 The general solution y C1y1 C2y2. yye
Note that there are three main differences between Frobenius Method and the Power Series Method: x x 0 is a regular singular point of the equation. The starting indices of y, y and y are 0. The value or values of r will need to be found. The equation used to solve r is called the indicial equation and solutions r 1 and r 2 are called the indicial roots. The indicial equation and its root(s) can be solved at advance from the equation: r r 1 a0r bwhere constants a 0 and b 0 are given in the series for xP x and x 2 Q x , respectively, i.e., : x x x0 P x
am x bm x
a1 x b1 x
a2 x b2 x
. and.
x0 2Q x
Example Solve 3xy a2 x 3x 0 when x
0 using Frobenius Method. y 1 3x 1 y 3x 1 a1 y 3x 0
0. Check the differential equation: xP x x2Q x x x2
both are analytic at x and its roots are:
1 x b0 1x 3x 0. So, x 0 is a regular singular point of the equation. The indicial equation: 1r r r r r 1 r r 3 r 0 or r 2. 3
2 is not an integer, there exist 2 linearly independent solutions in the form of a power Since r 2 r series centered at 0, i.e., 3
Find c m s. a. Let y
c m x m r. Then y
b. Substitute y, y and y into the differential equation: 3x
cm m 3c m m
r m r m r
1 xm 1 xm
r 2 m 0
cm m cm m
r xm r xm
r 1 m 0
cmxm cmxm
Replace m by k in the 1st and 2nd summation and replace m by k 1 in the 3rd summation. For the 3rd summation: m k 1, k m 1, when m 0, k 1. 3c k k
r k r k 2 xr
r r c0 r 1 xr
1 xk 1 xk xr
r 1 k 0
ck k ck k
r xk r xk
r 1 k 1 r 1 k 1
ck 1xk ck 1xk r 1 xk
3c k k
3c 0 r r c0 r 3 r c 0 r 3r c. The coefficient of x r
3c k k ck k
r k r 2
ck k ck
r 3k 3r
should be 0 :
c 0 r 3r 2 0. 2. (rs should be the same as the roots of the corresponding indicial Since c 0 0, r 0 or r 3 equation.) Coefficients of x k r 1 should be 0 : c k k r 3k 3r 2 c k ck r r 0, 2, 3 ck ck k 1 r 3k 3r 2 k ck 1, k 1, 2,.
1 ck 1, k 3k ck 1 k 2 3k and r
1, 2,. 1 k 3k 2 ck 1, k 1, 2,.
Derive recurrence relations of c k for r i. r 0,
c1 c2 c3
1 cc c7
c1 c0 c 8 2! 1 c c0 3! c3m 5. 1
k 2, 3 k k k 3
1 cc c11
1 cc c 2! 1 c c0 3! c3m 1. 5
k d. y
cmxm c c x
r1 m 0
cmxm 1 x2 8
1 x3. 168
c 02 x 2/3 1
1 x2 80
1 x3. 2640
1 xm 2 3m 5. xm 2 3m 1. 5
Example Solve xy a2 x x 0 when x
0. 0. Check the differential equation: xP x x2Q x x0 xx 0 x y a0 by x 0
0. So, x
0 is a regular singular point of the equation. The indicial equation is r r r r 1 a0r b0 r 0 and r 1.
Since r 2 r is a positive integer, there may be only one solution in the form of a power series centered c x m r. Find c m s. at 0 : y m 0 m c x m r. Then a. Let y m 0 m 5
b. Substitute y, and y into the differential equation: x
Replace m by k in the 1st and replace m by k 1 in the 2nd summation: m k 1, k m 1, when m 0, k 1. ck k
r k 1 xr
r 1 k 1
ck 1xk r k r 1
c0 r r c. The coefficient of x r
is 0 :
c0r r 1 0. Since c 0 0, r 0 or r 1 (Again, r s are the same as the solutions of the indicial equation.) Coefficients of x k r 1 are 0 : 1 ck 1, k 1, 2,. ck k r k r 1 ck ck k r k r ck 1, k 1, 2, 3,. it is not defined for k 1. For r 0, ck k k ck 1, k 1, 2,. For r 1, ck k 1 k i. r 0. The recurrence relation for c k is not defined. What does this mean? Observe that when k 1, c k k r k r 1 c k 1 c 0 c 0 c 0 0.
So, y ii. r 1,
c m x m is not a solution of the equation. k k k 3 c1 c2 ccccc0 2! 3! c0 3! 4! c0 1
1 c 1 c 144 0
1 cm! m
k d. y1
c0x 1 c0x 1
1 x1 m! m
1 x3. ! xm c0
1 m! m
y2 Px 1 dx y0,
P x dx x 1 xx x
xxx3 x 1 xx1 x1 x x
dx 1 x4. xx1x 1 x2 1x x5 x1 x19 x 72
7 x7 x1 x
229 x 736 x
11 x 3 288
5 xx 11 x x 4 dx x ln x 5 xx x 5 x x ln x 7 x 5 xx 4. y2 y1 x 19 x 7 x 5 xx 4. y 1 ln x y 1 x 19 x x4. xx 5 xx 4. x 1 x2 y 1 ln x x 1152 y 1 ln x 29 x xx 11 x 8. 5 xx 1 x x Observe that y 2 is of the form x 7 x 12 y 1 ln x
C2yx4. 1 x 4. ln x 1 xx3 C1 x 1 x2 C2 x 1 xx xx 11 x 8. 5 xx 1 x x e. Use a TI-89 calculator to find an approximation of y 2 : 1 x4. x 1 x2, P x 1 x3 y1 x 1 xi. y 1 x 1 x 2 x x 1 , F2, 3:expand(: expand(1/(x*(1-x/2)),x) 1 x y1 x 2 1x x F3, 9 taylor(: taylor(-1/(x-2),x,3) 3 x2 x 1, 1 x3 x2 x Answer: x x y2 ii. F2, 3:expand(: expand((1/x x^3/16 x^2/8 x/4 1/2)^2,x) 7
x5 3x 4 x3 5x 2 xx3 5x 2 x Now we have 2 x 16 y1 answer: iii. P x dx To evaluate 0dx C, e
1 x 3 4
1 e P x dx dx yx3 5x 2 x F3, 2: : 5x 3 x2 answer: ln|x| x 4 1x x 1 iv. To evaluate y 2 2
5x 2 x 3 dx x3 x x,x x 4 x3x x 5x 3 x2 3x x4 ln|x| x 40 4
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